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The value of e ≈ 2.71828 in java

 

The mathematical constant e (≈2.71828) is a cornerstone of modern mathematics, especially in calculus, exponential growth, and compound interest. Its history spans centuries of discovery and refinement. Here’s an overview:


What is e?

Ø  e is an irrational number (cannot be expressed as a simple fraction) and a transcendental number (not the root of any polynomial with rational coefficients).

Ø  It is the base of the natural logarithm and arises naturally in problems involving exponential growth, decay, and calculus.


Historical Milestones

1. Early Beginnings: Compound Interest

Ø  Jacob Bernoulli (1683):

ü  The origins of e trace back to problems in compound interest.

ü  Bernoulli studied the growth of money under continuous compounding. He calculated: $$\lim_{n \to \infty} \left(1 + \frac{1}{n}\right)^n$$

      • This limit equals e, showing how it arises naturally in financial mathematics.

2. Development of Logarithms

Ø  John Napier (1614):

ü  Napier developed logarithms to simplify calculations, laying the groundwork for e, though he did not explicitly define e.

ü  His logarithmic tables were implicitly based on a number close to e.


3. Euler’s Work (1727–1737)

Ø  Leonhard Euler was the first to formally define e as the base of natural logarithms.

Ø  Euler explored its properties in detail and introduced the exponential function \(e^x\).

Ø  He also discovered its connection to the famous Euler’s identity: $$e^{i\pi} + 1 = 0$$


4. Exponential Functions in Calculus

Ø  Isaac Newton and Gottfried Wilhelm Leibniz (Late 1600s):

ü  Both mathematicians used exponential growth and logarithmic functions in their development of calculus.

ü  e naturally emerged as the unique number where the derivative of \(e^x\) equals \(e^x\).


5. Growth and Decay in Real Life

Ø  By the 18th century, mathematicians realized that e models:

ü  Population growth.

ü  Radioactive decay.

ü  Heat transfer.

ü  Spread of diseases.

ü  Trigonometric calculation using infinite series.


Mathematical Definitions of e

e can be defined in several equivalent ways:

  1. Limit Definition:

$$e = \lim_{n \to \infty} \left(1 + \frac{1}{n}\right)^n$$

  1. Infinite Series:

$$e = \sum_{n=0}^\infty \frac{1}{n!} = 1 + \frac{1}{1!} + \frac{1}{2!} + \frac{1}{3!} + \dots$$

  1. Differential Equation: e is the unique number for which:

$$\frac{d}{dx}e^x = e^x$$


Applications of e

  1. Compound Interest:

ü  Continuous compounding of interest uses e: \(A = P e^{rt}\) Where A is the amount, P is the principal, r is the rate, and t is time.

  1. Calculus:

ü  e appears in derivatives and integrals of exponential and logarithmic functions.

  1. Physics and Engineering:

ü  Used in natural growth, decay, waveforms, and electrical circuits.

  1. Statistics:

ü  The normal distribution curve involves e in its probability density function.

  1. Computer Science:

ü  Used in algorithms, cryptography, and complexity analysis.


Modern Computation of e

Ø  With the advent of computers, millions of digits of e have been calculated.

Ø  Like π, e's digits continue infinitely without repeating.


 

 Mathematical e value derived:

The value of e≈2.71828 is derived from mathematical definitions and computations. Here's how we arrive at this number step by step:


1. Using the Limit Definition of e

The most intuitive way to compute e is through the limit definition:

$$e = \lim_{n \to \infty} \left(1 + \frac{1}{n}\right)^n$$

To approximate e, compute the expression for large values of n:

n

\(\left(1 + \frac{1}{n}\right)^n\)

1

2

10

2.59374

100

2.70481

1,000

2.71692

10,000

2.71815

1,000,000

2.71828

 

As n→∞n , the value converges to e≈2.71828.


2. Using the Infinite Series Definition

Another method is summing the infinite series:

$$e = \sum_{n=0}^\infty \frac{1}{n!} = 1 + \frac{1}{1!} + \frac{1}{2!} + \frac{1}{3!} + \dots$$

To approximate e, sum the first few terms:

 

n

Term \(\frac{1}{n!}\)

Cumulative Sum (e)

0

1

1.00000

1

1

2.00000

2

0.5

2.50000

3

0.16667

2.66667

4

0.04167

2.70834

5

0.00833

2.71667

6

0.00139

2.71806

7

0.00020

2.71826

8

0.00002

2.71828

 

 


n

Terms \(\frac{1}{n!}\)

\(e=e^1\)

0

\(\frac{1}{0!}\)

1.0000000000

1

\(\frac{1}{0!}+\frac{1}{1!}\)

2.0000000000

2

\(\frac{1}{0!}+\frac{1}{1!}+\frac{1}{2!}\)

2.5000000000

3

\(\frac{1}{0!}+\frac{1}{1!}+\frac{1}{2!}+\frac{1}{3!}\)

2.6666666666

4

\(\frac{1}{0!}+\frac{1}{1!}+\frac{1}{2!}+\frac{1}{3!}+\frac{1}{4!}\)

2.7083333333

5

\(\frac{1}{0!}+\frac{1}{1!}+\frac{1}{2!}+\frac{1}{3!}+\frac{1}{4!}+\frac{1}{5!}\)

2.7166666666

6

\(\frac{1}{0!}+\frac{1}{1!}+\frac{1}{2!}+\frac{1}{3!}+\frac{1}{4!}+\frac{1}{5!}+\frac{1}{6!}\)

2.7180555555

7

\(\frac{1}{0!}+\frac{1}{1!}+\frac{1}{2!}+\frac{1}{3!}+\frac{1}{4!}+\frac{1}{5!}+\frac{1}{6!}+\frac{1}{7!}\)

2.7182539682

8

\(\frac{1}{0!}+\frac{1}{1!}+\frac{1}{2!}+\frac{1}{3!}+\frac{1}{4!}+\frac{1}{5!}+\frac{1}{6!}+\frac{1}{7!}+\frac{1}{8!}\)

2.71827877698


Summing more terms gives better approximations of e.


Find out trigonometric equation from infinite series


 

We converted this formula to \(e^x\) terms formula

\(e^x=\frac{1}{0!}+\frac{x}{1!}+\frac{x^2}{2!}+\frac{x^3}{3!}+\frac{x^4}{4!}+\frac{x^5}{5!}+\frac{x^6}{6!}+\frac{x^7}{7!}+\frac{x^8}{8!}+ \dots\)

 

Now we know

\(sin(x)=\frac{x}{1!}-\frac{x^3}{3!}+\frac{x^5}{5!}-\frac{x^7}{7!}+ \dots\)

\(cos(x)=\frac{1}{0!}-\frac{x^2}{2!}+\frac{x^4}{4!}-\frac{x^6}{6!}+\frac{x^8}{8!}+ \dots\)


\( sin(x)+cos(x)=\frac{1}{0!}+\frac{x}{1!}-\frac{x^2}{2!}-\frac{x^3}{3!}+\frac{x^4}{4!}+\frac{x^5}{5!}-\frac{x^6}{6!}-\frac{x^7}{7!}+\frac{x^8}{8!}+ \dots\)

 

Both are identical; however, certain areas are positive while others are negative.

We have now adopted a different approach.

we converted this formula to \(e^{ix}\) terms formula

\(e^{ix}=\frac{1}{0!}+\frac{(ix)}{1!}+\frac{(ix)^2}{2!}+\frac{(ix)^3}{3!}+\frac{(ix)^4}{4!}+\frac{(ix)^5}{5!}+\frac{(ix)^6}{6!}+\frac{(ix)^7}{7!}+\frac{(ix)^8}{8!}+ \dots\)


where \(i=\sqrt{-1}\)

\(i^2=-1\)

\(i^3=i^2*i\)

\(i^4=i^2*i^2\)

 

\(e^{ix}=\frac{1}{0!}+\frac{(ix)}{1!}+\frac{(ix)^2}{2!}+\frac{(ix)^3}{3!}+\frac{(x)^4}{4!}+\frac{(ix)^5}{5!}+\frac{(x)^6}{6!}+\frac{(ix)^7}{7!}+\frac{(ix)^8}{8!}+ \dots\)

 

$$e^{ix}=\frac{1}{0!}+\frac{(ix)}{1!}+\frac{(ix)^2}{2!}+\frac{(ix)^3}{3!}+\frac{(x)^4}{4!}+\frac{(ix)^5}{5!}+\frac{(x)^6}{6!}+\frac{(ix)^7}{7!}+\frac{(ix)^8}{8!}+ \dots$$ $$= (\frac{1}{0!}-\frac{x^2}{2!}+\frac{x^4}{4!}-\frac{x^6}{6!}+\frac{x^8}{8!}+ \dots)+(\frac{ix}{1!}-\frac{ix^3}{3!}+\frac{ix^5}{5!}-\frac{ix^7}{7!}+ \dots)$$ $$= (\frac{1}{0!}-\frac{x^2}{2!}+\frac{x^4}{4!}-\frac{x^6}{6!}+\frac{x^8}{8!}+ \dots)+i(\frac{x}{1!}-\frac{x^3}{3!}+\frac{x^5}{5!}-\frac{x^7}{7!}+ \dots)$$ $$=cos(x)+isin(x)$$

When x = π

Then

\(e^{i\pi} =cos(\pi)+i.sin(\pi)=-1+0\)

\(\bbox[yellow]{e^{i\pi} +1=0}\)


3. Using Continued Fractions

The value of e can also be approximated using its continued fraction representation:

$$e = 2 + \frac{1}{1 + \frac{1}{2 + \frac{1}{1 + \frac{1}{1 + \frac{1}{4 + \dots}}}}}$$​

Computing this continued fraction iteratively also converges to e.


4. Using Numerical Computation (Programming)

Programming languages like Java can compute e to high precision. Here's how:

java:

public class ComputeE {

    public static void main(String[] args) {

        double r = 0.1; // Interest rate

        double ePowerR = Math.exp(r); // Calculate e^r

        double principal = 1000;

        double amount = principal * ePowerR;

        System.out.printf("Amount with continuous compounding: $%.2f%n", amount);

    }

}

 

Custom Exponential Java class:

public class CustomMathExp {

 

    public static double customExp(double r, int terms) {

        double result = 1.0; // The sum starts with the first term: 1

        double term = 1.0;   // Each term in the series

 

        for (int i = 1; i <= terms; i++) {

            term *= r / i;  // Calculate the next term: (r^i / i!)

            result += term; // Add the term to the result

        }

 

        return result;

    }

 

    public static void main(String[] args) {

        double r = 1.0; // Example input

        int terms = 20; // Number of terms for approximation

 

        // Using custom implementation

        double customResult = customExp(r, terms);

 

        // Using built-in Math.exp for comparison

        double mathResult = Math.exp(r);

 

        System.out.printf("Custom Math.exp(%f): %.15f%n", r, customResult);

        System.out.printf("Built-in Math.exp(%f): %.15f%n", r, mathResult);

        System.out.printf("Difference: %.15f%n", Math.abs(customResult - mathResult));

    }

}

 

Output Example

For r=1.0r = 1.0r=1.0 and terms=20terms = 20terms=20:

Custom Math.exp(1.000000): 2.718281828459045

Built-in Math.exp(1.000000): 2.718281828459045

Difference: 0.000000000000000

 




5. Using a Calculator

Many scientific calculators have a dedicated e key. Alternatively, you can compute \(e^1\) or evaluate the series/limit definitions to approximate the value.


 Compound interest Story:

The story of compound interest involves calculating how investments grow when interest is calculated and added to the principal at regular intervals. The frequency of compounding—whether it's secondly, minutely, hourly, daily, weekly, monthly, or yearly—determines how much interest accrues over a given period. Here's an explanation of how compound interest works and how to calculate the maximum possible interest in different scenarios.


Compound Interest Formula

The standard formula for compound interest is:

$$A = P \left(1 + \frac{r}{n}\right)^{n \cdot t}$$

Where:

Ø  A = Final amount (principal + interest)

Ø  P = Principal amount (initial investment)

Ø  r = Annual interest rate (in decimal form)

Ø  n = Number of times interest is compounded per year

Ø  t = Time in years


Scenarios for Different Compounding Frequencies

As n (the frequency of compounding) increases, the final amount A approaches a maximum value. This happens because as compounding becomes more frequent, the growth mimics continuous compounding, governed by the mathematical constant e.

1. Yearly Compounding (n=1)

Ø  Interest is added once per year.

$$A = P \left(1 + r\right)^t$$

2. Monthly Compounding (n=12)

Ø  Interest is added 12 times a year.

$$A = P \left(1 + \frac{r}{12}\right)^{12 \cdot t}$$

3. Weekly Compounding (n=52)

Ø  Interest is added 52 times a year.

$$A = P \left(1 + \frac{r}{52}\right)^{52 \cdot t}$$

4. Daily Compounding (n=365)

Ø  Interest is added daily (assuming no leap years).

$$A = P \left(1 + \frac{r}{365}\right)^{365 \cdot t}$$

5. Hourly Compounding (n=8760)

Ø  Interest is added every hour (24 hours × 365 days).

$$A = P \left(1 + \frac{r}{8760}\right)^{8760 \cdot t}$$

6. Minutely Compounding (n=525600)

Ø  Interest is added every minute (60 minutes × 24 hours × 365 days).

$$A = P \left(1 + \frac{r}{525600}\right)^{525600 \cdot t}$$

7. Secondly Compounding (n=31536000)

Ø  Interest is added every second (60 seconds × 60 minutes × 24 hours × 365 days).

$$A = P \left(1 + \frac{r}{31536000}\right)^{31536000 \cdot t}$$


Continuous Compounding (Maximum Interest)

As \(n \to \infty\), the compound interest formula becomes:

$$A = P \cdot e^{r \cdot t}$$

Here:

Ø  e≈2.71828 (the base of natural logarithms).

Ø  This represents the theoretical maximum interest for a given annual rate r and time t.


Comparison of Different Frequencies

Assume:

Ø  Principal (P) = $1,000

Ø  Annual interest rate ® = 10% (0.1)

Ø  Time (t) = 1 year

Compounding Frequency

Amount ($)

Extra Interest Over Yearly ($)

Yearly (n=1)

1,100.00

0

Monthly (n=12)

1,104.71

4.71

Weekly (n=52)

1,105.06

5.06

Daily (n=365)

1,105.16

5.16

Hourly (n=8760)

1,105.17

5.17

Minutely (n=525600)

1,105.17

5.17

Secondly (n=31536000)

1,105.17

5.17

Continuous (n→∞n)

1,105.17

5.17

 


Insights

  1. Diminishing Returns:

Ø  As compounding frequency increases, the added interest becomes negligible after daily compounding.

Ø  Continuous compounding represents the theoretical maximum.

  1. Practical Limits:

Ø  Financial institutions typically offer daily or monthly compounding. Second-by-second or continuous compounding is rarely implemented in practice.

  1. Real-Life Applications:

Ø  Continuous compounding is used in advanced financial modeling, physics (exponential decay/growth), and biology.


Conclusion

The story of compound interest shows how increasing compounding frequency results in more interest, but the benefits diminish as the intervals shorten. Continuous compounding, driven by the natural constant e, provides the theoretical upper limit for growth, reflecting nature’s most efficient way to grow exponentially.

 

Key Takeaway

The constant e represents the natural growth rate and is deeply tied to real-world phenomena, from finance to biology. Its discovery and exploration have shaped calculus and mathematics as we know it today, making it one of the most important constants in mathematics.

 

Historical Note

Ø  The concept of e was introduced in the context of compound interest and exponential growth.

Ø  Jacob Bernoulli discovered the limit definition while studying compound interest in 1683.

Ø  Leonhard Euler, who formalized e, showed its connection to logarithms, calculus, and series.

Thus, e=2.71828 represents one of the most fundamental constants in mathematics and nature.

 

The value of e
The value of e




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