The classic "100 Doors" puzzle, where you toggle
doors between open and closed based on certain conditions. However, there are a
few logic errors and areas of improvement. Let's go through the current code
and then discuss how to improve it.
Current Code Summary:
- Toggling
Logic: The way you're toggling doors is not clear, especially with k *
(k + 2). It should follow a pattern where each door is toggled based on
the number of passes. For example:
Ø
On the 1st pass, every door is toggled (i.e.,
all doors are opened).
Ø
On the 2nd pass, every 2nd door is toggled
(i.e., doors 2, 4, 6, etc.).
Ø
On the 3rd pass, every 3rd door is toggled
(i.e., doors 3, 6, 9, etc.).
Ø
This continues until the 100th pass.
- Number
of Passes: You need to simulate toggling the doors for each
"pass," not just 10 times as your loop currently does.
- Efficiency:
The list of open doors is printed for each iteration, which is not
necessary. You could instead toggle the doors and print the result at the
end.
Code:
java
package
com.kartik.puzzle.door; import
java.util.ArrayList; import
java.util.List; public class
Doors { public static void main(String[] args) { int numberOfDoors = 100; boolean[] doors = new
boolean[numberOfDoors]; // Simulating 100 passes for (int pass = 1; pass <=
numberOfDoors; pass++) { for (int door = pass - 1; door
< numberOfDoors; door += pass) { // Toggle the door state doors[door] = !doors[door]; } } // List to hold open door information List<String> openDoorInfoList =
new ArrayList<>(); // Check which doors are open for (int i = 0; i < numberOfDoors;
i++) { if (doors[i]) { String openDoorInfo =
"Door #" + (i + 1) + " is open.";
openDoorInfoList.add(openDoorInfo); } } // Print all open doors System.out.println("<----
Open Doors ---->"); for (String openDoor :
openDoorInfoList) { System.out.println(openDoor); } } } |
Explanation of Changes:
- Toggling
Logic: The inner loop now correctly toggles the doors based on the
current pass. For example, on the 1st pass, every door is toggled. On the
2nd pass, every 2nd door is toggled, and so on.
Ø
door += pass: This ensures that for each pass,
only doors that are multiples of the pass number are toggled.
- Single
Loop for Output: Instead of printing the open doors at every pass, the
code now stores the information and prints it once, after all passes are
completed.
Output:
The output will display the doors that are open after 100
passes. For the "100 Doors" puzzle, the doors that remain open are
those whose door numbers are perfect squares (because they have an odd number
of factors, leading them to be toggled an odd number of times).
<----Only
open door---> |
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